How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas? Unbalanced equation: C2H6 + O2 ----> CO2 + H2O Show, or explain, all of your work along with the final answer.
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OpenStudy (epicteatime):
@iPwnBunnies
OpenStudy (epicteatime):
balanced equation: 2C2H6 + 7O2 --> 4CO2 + 6H2O
OpenStudy (ipwnbunnies):
This is easy man. Look at the equation. Use stoichiometry (mole ratios). What's the ratio of water to ethane?
OpenStudy (epicteatime):
2:6?
OpenStudy (epicteatime):
or the other way round?
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OpenStudy (ipwnbunnies):
Other way around. 6 mol H20/2 mol C2H6
OpenStudy (epicteatime):
oh ok
OpenStudy (ipwnbunnies):
This is saying we can make 6 moles of water if we have 2 moles of ethane (w/ unlimited O2).
OpenStudy (epicteatime):
ok
OpenStudy (ipwnbunnies):
So, go back to your problem. We have 11.7 moles of ethane. Can you do some math with the mole ratio to figure out how many moles of water that can make?
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OpenStudy (epicteatime):
maybe?
OpenStudy (ipwnbunnies):
Yes, you can lol.
OpenStudy (ipwnbunnies):
You have 11.7 moles ethane and the mole ratio 2 moles of H2O to 6 moles of ethane.
OpenStudy (epicteatime):
11.7g C2H6 x 6/2
OpenStudy (ipwnbunnies):
There ya go man. That'll give us the amount of moles of water that can be made from 11.7 moles of ethane and excess O2.
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OpenStudy (epicteatime):
35.1g
OpenStudy (ipwnbunnies):
Wrong. We'll have 35.1 moles of H2O. Don't mess it up. We use mole ratios in chemical equations to figure out how many MOLES something has.
OpenStudy (epicteatime):
ok
OpenStudy (ipwnbunnies):
To find the mass, we have to multiply the amount of moles by the molar mass. Do you know the molar mass of H2O? You can find it with the Periodic Table.
OpenStudy (epicteatime):
18.01?
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OpenStudy (epicteatime):
since it's 1.0079 x 2 + 15.999 right?
OpenStudy (ipwnbunnies):
Yes. H20 has a molar mass of 18.01 grams per mol.
OpenStudy (epicteatime):
ok
OpenStudy (ipwnbunnies):
Can you figure out the mass of 35.1 moles of H2O now?
OpenStudy (epicteatime):
how do i dot that?
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OpenStudy (ipwnbunnies):
Check out the units of both. How can we cancel out the moles and be left with grams?
OpenStudy (ipwnbunnies):
Wrong.
OpenStudy (epicteatime):
;P
OpenStudy (ipwnbunnies):
If 18.01 grams is the mass of one mole, how much will 35.1 moles be?
OpenStudy (epicteatime):
1.95g?
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OpenStudy (ipwnbunnies):
\[(35.1 mol H2O)(18.01 \frac{grams}{mol}) =\]
OpenStudy (epicteatime):
35.1/18.01
OpenStudy (epicteatime):
is it x?
OpenStudy (ipwnbunnies):
Why would you divide. Look at the units man. The units tell you the answer. You can solve lots of problems looking at the units. Yes, multiply.
OpenStudy (epicteatime):
ok
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OpenStudy (epicteatime):
And, i don't know, I'm obsessed with division i guess...
OpenStudy (epicteatime):
wait,35.01 x 18.01?
OpenStudy (epicteatime):
is it 632.2
OpenStudy (ipwnbunnies):
Yeah. 35.01 moles times 18.01 grams per mol.
OpenStudy (ipwnbunnies):
Sure.
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OpenStudy (epicteatime):
i DON T UNDERSTAND... ;(
OpenStudy (ipwnbunnies):
35.1 moles*
How do you not understand? I literally explained it as clear as I can.
OpenStudy (epicteatime):
jk
OpenStudy (epicteatime):
so it is 632.2?
OpenStudy (ipwnbunnies):
No. That's a number.
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OpenStudy (ipwnbunnies):
We want to know the mass of the water. Use units.
OpenStudy (epicteatime):
ok
OpenStudy (epicteatime):
...
OpenStudy (epicteatime):
i keep getting that!! 632.2g
OpenStudy (ipwnbunnies):
Good.
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