Question

For the given function, find the vertical and horizontal asymptote(s) (if there are any).

f(x) = x-5/x^2-1

Answer 1

Vertical: find where the denominator equals zero.

Answer 2

wait so its verical

Answer 3

That's how you find verticals.

Horizontal: if the denominator is a higher degree than the numerator, then the asymptote is y=0

Answer 4

vetical

Answer 5

...? These are how you find the vertical and horizontal asymptotes.

Answer 6

x^2-1 = 0 will find V.A.

Horizontal: if the denominator is a higher degree than the numerator, then the asymptote is y=0

Answer 7

x^2=1

Answer 8

x^2-1 is a difference of two squares

Answer 9

(x+1)(x-1) = 0

Answer 10

x = 5, y = 0

Answer 11

you forgot (x+1)(x-1) = 0

Answer 12

x=5 is a zero or x-intercept. Not asymptote.

Answer 13

x = 1, x = -1, y = 0