Question

Find a cubic function with the given zeros.

6, -5, 2

Answer 1

If a , b and c are the three zeros of a cubic polynomial with the variable x
then you can find out the equation by
(x-a) ( x-b) ( x - c ) = 0

Answer 2

give it a try @melacho ... try to solve it now

Answer 3

ok you beat me to it lol

Answer 4

i still dont get it :>

Answer 5

haha @kirbykirby

Answer 6

@melacho ... the given zeros are 6 , -5 , 2
and let
6 be a... i.e. 6 = a
-5 be b ...i.e. -5 = b
and
2 be c ..... i.e. 2 = c

Now... try to use these values in
(x-a) ( x-b) ( x - c ) = 0

Answer 7

(x-6) (x-(-5)) (x-2)=0?

Answer 8

yup..!

Answer 9

You want a function, so just make it
f(x) = (x-6) (x+5) (x-2)

Answer 10

but these are my choices
f(x) = x3 - 3x2 + 28x + 60

f(x) = x3 - 3x2 - 28x - 60

f(x) = x3 + 3x2 - 28 + 60

f(x) = x3 - 3x2 - 28x + 60

Answer 11

Multiply it out.

Answer 12

If you're not sure where this idea is coming from, you can try googling "Factor Theorem". It essentially states that if "a" is a zero of a polynomial, then (x-a) is a factor of the polynomial. Hence, that is why @Shizen suggested using (x-a)(x-b)(x-c)

Answer 13

Multipy any of the two factors first and then multiply the result with the third one....

Answer 14

f(x) = (x-6) (x+5) (x-2)

first multiply (x-6) (x+5)
then multiply that result by (x-2)

Answer 15

f(x) = x3 - 3x2 - 28x - 60

Answer 16

well.. just recalulate the constant term....

Answer 17

f(x) = x3 - 3x2 + 28x + 60

Answer 18

Can you show me, the way you are solving it ??
cos you are commiting a mistake....

Answer 19

f(x) = x3 + 3x2 - 28 + 60

Answer 20

i did:

Answer 21

x3 + 3x2 - 28 + 60

well you missed the x after -28...:D...

Answer 22

f(x) = x3 - 3x2 - 28x + 60

Answer 23

ahaan,..! thats correct....:D