Question

f(x) has a m=-1/x^2 and passes through P (1/5,12)
find the curve y=f(x) in the xy plane

Answer 1

?

Answer 2

\(\large \frac{dy}{dx} = \frac{-1}{x^2}\)

Answer 3

take the integral

Answer 4

\(\large y = \int \frac{-1}{x^2}dx\)

Answer 5

1/x +C

Answer 6

So,

\(\large y = \frac{1}{x} + C\)

is the required curve ?

Answer 7

1/x + 1/5 ?

Answer 8

i am not sure, have to use point

Answer 9

since the curve goes thru the point P(1/5, 12),
plugin x = 1/5 and y = 12 in equation

Answer 10

12=1/(1/5)+C

Answer 11

c=7

Answer 12

\(\large y = \frac{1}{x} + C\)

plugin, x = 1/5, y = 12

\(\large 12= \frac{1}{1/5} + C\)

\(\large 12= 5 + C\)

\(\large 7= C\)

Answer 13

yes, plug c value in ur equation

Answer 14

so answer is
y=1/x +7

Answer 15

Yes !

Answer 16

cool thanks

Answer 17

u wlc !