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Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = 8/square root of quantity 2x+4 @agent0smith
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Realize that is equivalent to multiplying 8 by (2x+4)^-1/2
\[\Large y = \frac{ 8 }{ \sqrt {2x + 4} }\] You could let g(x) = sqrt(2x+4) and f(x) = 8/x
16x+32^-1/2
f(x) = 8, g(x) = square root of quantity two x plus four.
f(x) isn't just 8
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8/sqrt x
Now you'd have too many square roots. I already posted something that would work above
eight divided by square root of x., g(x) = 2x + 4
That works too.
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