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Mathematics 8 Online
OpenStudy (anonymous):

When are you supposed to use these within trigonometric equations?

OpenStudy (anonymous):

For example; If you end up with the answer \[\frac{ \pi }{ 4 } and \frac{ \pi }{ 6 } \] How do you know if its supposed to be \[\frac{ \pi }{ 4 } + 2k pi\] \[\frac{ \pi }{ 4 } + k pi \]

OpenStudy (anonymous):

I meant to put or between the last 2 equations

OpenStudy (anonymous):

Is your question when do you include that in your answer, or which one do you use?

OpenStudy (anonymous):

Sorry, but I don't get your question here.

OpenStudy (unklerhaukus):

\[\sin(\theta\pm2n\pi)=\sin(\theta)\] \[\cos(\theta\pm2n\pi)=\cos(\theta)\] \[\tan(\theta\pm n\pi)=\tan(\theta)\]

zepdrix (zepdrix):

Example problem:\[\Large\bf\sf \sin x=\frac{\sqrt2}{2}\]Solving for x gives us,\[\Large\sf \frac{\pi}{4}\text{ and }\frac{3\pi}{4}\]But since we want ALL angles that produce sqrt2/2, we have to allow for full rotations around the unit circle that land us in the same spot. So your solution would be,\[\Large x=\cases{\frac{\pi}{4}+2k \pi, \\\frac{3\pi}{4}+2k \pi, \qquad k=0,\pm1,\pm2,...}\] ------------------------------------------------------------ Alternatively, if you're given the same problem but with a small change,\[\Large\sf \sin x=\frac{\sqrt2}{2},\qquad \qquad 0\le x\lt 2\pi\]This inequality is telling us that we only want the solution in one rotation around the unit circle. So we would have the same solution but without the +2kpi.

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