Question

Given the functions
h:x: 4x + m
and
h^-1:x : 2kx + 5/8 ,
where m and k are constants,
find the value of m and of k.

Answer 1

@crazysingh can you help me?

Answer 2

wait i am trying .

Answer 3

is \[m = \frac{ -5 }{ 2 } ; k = \frac{ 1 }{ 8 }\]

am i correct ?

Answer 4

whoa, correct!

Answer 5

ok i will explain.

Answer 6

first find inverse of h(x) by substituting x by y and y by and solve for y = f(x). f(x) will be inverse of the given function h(x).

\[y= 4x+m\] so

\[x = \frac{ y-m }{ 4 } = \frac{ 2y-2m }{ 8 }\]

now substitute x by y and y by x to get the inverse.

\[y = \frac{ 2x-2m }{ 8 }\] .. [I]

above equation represents inverse of the function. compare it with given inverse function. which is \[h ^{-1}(x) = 2kx + \frac{ 5 }{ 8 } = \frac{ 16kx+5 }{8 }\] .. [II]


compare [I] and [II] to get values of k and m.

Answer 7

let me try it first.

Answer 8

why must the equation times with 2