find the laplace inverse transform
F(s)=(s+2)/(s^2-3s+4)

Question

find the laplace inverse transform
F(s)=(s+2)/(s^2-3s+4)

mathmale · Answer

What have you done in previous problems like this one?  What would the first steps be?

unklerhaukus · Answer

complete the square in the dominator

mathmale · Answer

Yes, but for what purpose?  What would the very first goal be in attacking this problem, and why?

unklerhaukus · Answer

if you complete the square in the denominator you can apply the shift theorem

anonymous · Answer

To check your answer, visit http://www.wolframalpha.com/input/?i=inverse+lapalace+transform+%28s%2B2%29%2F%28s^2-3s%2B4%29

anonymous · Answer

$$inverse L=s/((s-3/2)^2+7/4) +2/((s-3/2)^2+7/4)... then ? im stuck$$

mathmale · Answer

I'd suggest you look at this table of Laplace Transforms and determine for yourself which one or two of the transform pairs would be best suited to apply to your Laplace transform problem. http://tutorial.math.lamar.edu/Classes/DE/Laplace_Table.aspx

mathmale · Answer

I would write your particular Laplace transform as $$F(s) = \frac{ s+2 }{ (s-\frac{ 3 }{ 2 })^2+(\frac{ \sqrt{7} }{ 2 } )^2}$$

mathmale · Answer

Think:  How could you modify this Laplace transform so that you could use one or more of the Laplace transform pairs in the table to find the inverse Laplace transform of F(s)?

mathmale · Answer

Were it up to me, I'd use the pairs #19 and #20.
Good luck!