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Physics 18 Online
OpenStudy (anonymous):

Who can do this? Air at atmospheric pressure(760 mm Hg) is trapped inside a container as shown in the diagram

OpenStudy (anonymous):

|dw:1396196816458:dw|

OpenStudy (anonymous):

When the piston is pulled slowly so that the volume is increased by 20%, the temperature remaining constant, the pressure of the air becomes A) 912 mm Hg B) 950 mm Hg C) 608 mm Hg D) 633 mm Hg

OpenStudy (rajat97):

the answer is (D) and you can do it by assuming it to be an isothermal process for an isothermal process, P1V1=P2V2 where P1 and V1 are the initial pressure and volume and P2 , V2 are the final pressures and volumes so here, P1=760(mm of hg) V1=V(i have assumed it to be V) V2=1.2V as the question says that the final volume is increased by 20% we getP2=633mm of hg i hope this helps you:)

OpenStudy (rajat97):

hey @Gebooors thanks for the medal!

OpenStudy (rajat97):

thanks for the medal @sheelo73mughal

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