A stretched string is fixed at both ends which
are 550 cm apart.
If the density of the string is 0.035 g/cm,
and its tension is 600 N, what is the wave-
length of the 8th harmonic?
Answer in units of cm

Question

A stretched string is fixed at both ends which
are 550 cm apart.
If the density of the string is 0.035 g/cm,
and its tension is 600 N, what is the wave-
length of the 8th harmonic?
Answer in units of cm

rajat97 · Answer

135cm???

anonymous · Answer

Sadly that was incorrect :/ but do you have an idea for a formula to solve this?

rajat97 · Answer

i just drew th diagram for eighth harmonic!
or else, you can use the formula
f=n(vw)/2l where n denotes the nth harmonic

rajat97 · Answer

is it 137.5cm??

rajat97 · Answer

i think it was again a calculation mistake in the previous question

anonymous · Answer

That was correct :) and thank you for the formula

rajat97 · Answer

yeah you're welcome!

rajat97 · Answer

thanks for the medal!