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A curve has equation y=2x^(3/2) +1. Calculate the gradient of the curve at: x=4
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have you learn differentiating?
All you need to find is y'(4)
Yeah I have, but I'm pretty certain we have to use the f(x+h) - f(x) / h formula. Just don't know how to work it with the powers.
Really? That's all you do?
yep
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Wow I was making this much more difficult than it was. Thanks a lot :)
\[ y'(x)=2 x^{3/2}+1 \]
Compute now y'(4) and you are done.
\(y'(x)=3x^{\frac{1}{2}}\)
\[f'(x)=3x ^{1/2}\], Isnt that the derivative?
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Oh there we go then, so the gradient = 6?
yeah, i got the same thing
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