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OpenStudy (anonymous):
with?
OpenStudy (anonymous):
physics
OpenStudy (anonymous):
go ahead and ask your question
OpenStudy (anonymous):
question is a train start from a station and moves with a constant acceleration for 2 min . if it covers adistance of 400 m in this period , find the acceleration
OpenStudy (anonymous):
3.334 m/s?
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OpenStudy (anonymous):
wrong
OpenStudy (anonymous):
acceleration is v-v/t so you can solve for velocity which is distance over time
OpenStudy (anonymous):
yes. acceleration is change in velocity divided by time
OpenStudy (anonymous):
but ans is 1/18 m/s^2
OpenStudy (anonymous):
any body say something
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OpenStudy (anonymous):
I got 1/36 but if you need something else you can post this question on the physics part of openstudy and most likely those guys could help you better
OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
\(\large v = at\)
integrate both sides
\(\large \int v~dt = \int at~dt\)
\(\large s = a\frac{t^2}{2}\)