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Mathematics 11 Online
OpenStudy (anonymous):

i need help

OpenStudy (anonymous):

with?

OpenStudy (anonymous):

physics

OpenStudy (anonymous):

go ahead and ask your question

OpenStudy (anonymous):

question is a train start from a station and moves with a constant acceleration for 2 min . if it covers adistance of 400 m in this period , find the acceleration

OpenStudy (anonymous):

3.334 m/s?

OpenStudy (anonymous):

wrong

OpenStudy (anonymous):

acceleration is v-v/t so you can solve for velocity which is distance over time

OpenStudy (anonymous):

yes. acceleration is change in velocity divided by time

OpenStudy (anonymous):

but ans is 1/18 m/s^2

OpenStudy (anonymous):

any body say something

OpenStudy (anonymous):

I got 1/36 but if you need something else you can post this question on the physics part of openstudy and most likely those guys could help you better

OpenStudy (anonymous):

ok

ganeshie8 (ganeshie8):

\(\large v = at\) integrate both sides \(\large \int v~dt = \int at~dt\) \(\large s = a\frac{t^2}{2}\)

ganeshie8 (ganeshie8):

plugin \(s = 400\), \(t = 2\times 60 \) and solve \(a\)

ganeshie8 (ganeshie8):

\(\large 400 = a\frac{(2\times 60)^2}{2}\)

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