Question

Integration Help...

Answer 1

\[\int\limits_{1}^{2} \frac{ x-4 }{ x ^{2}} dx\]
I got ln2+2 as my answer but the correct answer is ln2-2

Answer 2

I think you did a mistake when substituting in 2 and 1

Answer 3

\[\Large [\ln(x)+\frac{4}{x}]^{2}_{1}\]
\[=\ln(2)+2-4\]

Answer 4

ohh i did -4/x
can you show me how you got that?

Answer 5

\[\Large [\ln(x)+\frac{4}{x}]^{2}_{1}\]
\[\Large [\ln(2)+\frac{4}{2}]-[\ln(1)+\frac{4}{1}]\]
\[=\ln(2)+2−4\]

Answer 6

\[\int\limits\limits_{1}^{2} \frac{ x-4 }{ x ^{2}} dx\]
\[\int\limits\limits_{1}^{2} \frac{1}{x}-\frac{4}{x^2} dx\]
Integrate using power rule you get
\[[\ln(x)+\frac{4}{x}]^{2}_{1}\]

Answer 7

ahh i see! thank you :)

Answer 8

yw