Question

Find the integral of dx/x^(1.01) from 1 to infinity.

Answer 1

@beccaboo333

Answer 2

\(\Large x^{1.01}=(x^1)^{\frac{1}{100}}x=x^{\frac{101}{100}} = \sqrt[100]{x}^{101} \)

Answer 3

\[\int\limits_{1}^{\infty}x ^{1.01}dx=\frac{ x ^{2.01} }{ 2.01 }~from~1~\to~\infty approaches~\to~\infty \]\]because x>1

Answer 4

Isn't it 1/x^(1.01) dx?

Answer 5

no matter how you look at it, both answers demonstrate that you're integrating a polynomial, and you know how to integrate these I presume. Use the regular formula.

Answer 6

i forgot to see / sign in that case write -1.01 in the exponent

Answer 7

Never mind, I got it by using the regular formula. Thank you, Spacelimbus.

Answer 8

after solving answer no infinity some real no.you can solve it ,if any problem i will help you.