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Power series representation for: f(x) = (1+x^2)^(-2/3) I know we're supposed to use the taylor series: 1/(1+x) = (summation) ((-1)^k) * (x^k) for |x| <1 but I'm not entirely sure what to do about the power (2/3) when you flip it.
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What I have so far: \[\sum_{k=0}^{\infty} (-1)^k \times x^{2k}\]
What do you mean about the power (-2/3) when you "flip it"?
I flipped the given equation to: \[{1/(1+x^2)}^{2/3}\]
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