Question

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Create a quadratic equation in standard form that can be factored.

Answer 1

a.)Write your equation in standard form. Use complete sentences to explain the benefits of writing your equation in standard form.
b.Write your equation in factored form. Use complete sentences to explain the benefits of writing your equation in factored form.
c.Write your equation in vertex form. Use complete sentences to explain the benefits of writing your equation in vertex form.
Explain how all three forms can be used together to help you graph a quadratic function. Graph your function and label the y-intercept,

Answer 2

@AccessDenied

Answer 3

@Squirrels

Answer 4

@Loser66

Answer 5

@mathstudent55

Answer 6

@myininaya

Answer 7

@poopsiedoodle

Answer 8

@jdoe0001

Answer 9

where are you stuck at?

Answer 10

part a lol

Answer 11

\[ax^2+bx+c=0 \] is the form where quadratic equation in standard form looks likes
where a, b , c are constant.

Answer 12

can you think of numbers for a, b , and c that could be factored

Answer 13

2,4 and 6?

Answer 14

you can not factor that, now can you?

Answer 15

I don't really know im really bad at math :/

Answer 16

do you know what factoring is?

Answer 17

one of two or more numbers, algebraic expressions when multiplied together produce a product?

Answer 18

@helpme1.2

Answer 19

okay.. but do you actually know how to factor out quadratic equation?

Answer 20

nope

Answer 21

sooo where do we go from here?

Answer 22

i'll create numbers for a,b, and c, that could be factored
a = 1
b = 4
c = 3
so the equation would look like \[x^2+4x+3 = 0 \] that would be the quadratic equation in standard form

Answer 23

for factoring,
i suggest you visit, http://www.mathsisfun.com/algebra/factoring-quadratics.html to learn more about it, and try to factor \[x^2 + 4x+3 = 0\]

Answer 24

c, it says, you need to write it in vertex form
and if you don't know what a vertex form looks like or how to get to vertex form from quadratic equation, then you should visits
http://www.purplemath.com/modules/sqrvertx.htm
to have more understanding

Answer 25

and d?

Answer 26

when you factor it out
you would find 2 x values
use them as x axis point, for y axis, they would be just zero, and connect the point on the graph
you can use this, to check your graphing http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html

Answer 27

for part b would the answer be (x+3) (x+1)?

Answer 28

@helpme1.2

Answer 29

yes

Answer 30

I know what a vertex form looks like but I don't know how to actually get to it, I looked over that page but it didn't really help

Answer 31

so we have
\[x^2 + 4x + 3 \]take half of b val which is 4, and square it and add it to it, then subtract it to 3
\[(x^2 + 4x + 2^2) + 3- 2^2 \] \[(x^2 +4x+4) +3-4 \]then you would have a perfect square
\[(x+2)^2 - 1 \]--> vertex form

Answer 32

thanks :) I really appreciate your help

Answer 33

No problem