Please Help: 1)What would be the weight of 1.45 moles of nitric acid? I found the GMW=63.I think I would have to divide 63 by 12 and get 5 moles, but I do not know what to do next.
@Loser66 @phi
@robtobey @shamil98
@arabpride @linda3 @SoloN8v88
I don't know ~ i dont even take chem. srry.. *^.^*
try this website. it has a calculator on here that might be helpful to you http://www.sigmaaldrich.com/chemistry/stockroom-reagents/learning-center/technical-library/molarity-calculator.html
@arabpride thanks for looking :)
Your're very welcome *^.^*
@darkest_midnight i tried the website but it didnt help
Do you know the molecular formula for nitric acid?
I'm sorry :( well i see here that the density for nitric acid is 1.413 g per milliliter and the formula weight is 63.01 per mole....
No we don't.
That information is all the info the problem gave me @darkest_midnight @iPwnBunnies is it HNO3
We have the amount of moles of nitric acid, and we have the molar mass of the nitric acid. We can find the mass of it.
Do you need the mass or the weight? You can convert grams to some weight I guess.
bunnies shall help you lol
i need the Weight of 1.45 moles of HNO3
Ok, I'll just assume that means mass. Darkest already told us that one mole of HNO3 is 63.01 grams.
ok
But we have 1.45 moles sooooo: \[mass HNO3 = (1.45 moles)(\frac{63.01 grams}{mole})\]
so the answer would be 91.35 grams?
Idk, I didn't do the math lol. That is the mass of the HNO3. I don't know what units you want for weight, so that's as far as we can go. Maybe your assignment means mass.
Yes, it is 91.35 grams.
thank you for the help @iPwnBunnies
now, what i said was 63.01 grams. that was the assumed calculation from the formula that automatically appeared when i selected nitric acid.
That's the molecular mass for nitric acid, HNO3. 1.01 amu + 14 amu + 3(16 amu) = 63.01 amu = 63.01 g/mol
just making sure that's right. I hate giving people wrong answers.
amu is an obsolete unit. Use daltons.
Is it really?
I still see 'amu' used.
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