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OpenStudy (anonymous):
How do you find the oxidation number of Na2SeO3
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OpenStudy (anonymous):
Na would be 2(1) which is 2.... you get the 1 since Na is in the first group so the oxidation number will be 1 oxygen oxidation number is always -2 so you multiply it by 3(-2)= -6 2-6=4 so the oxidation number for Se is 4 cause thats the only way it will = 0 on the total
OpenStudy (kaederfds):
whose oxinumber do you mean?
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