Question

can someone please explain this to me:
A local FM radio station broadcasts at an energy of 6.18E-29 kJ/photon.

Calculate the frequency at which it is broadcasting.
Frequency = MHz

Answer 1

Use plank's equation: \(E_{photon}=h\nu\)

This will give you the frequency in Hz, so you'll have to convert.
Also convert kJ to J before plugging it in.

Answer 2

okay so i converted and i got 6.18E-26J/photon..... then h=6.626E-34Jsec...so what would i put for E and for v

Answer 3

E is energy, J is unit of energy. \(\nu\) is frequency, what you're solving for.

Answer 4

so how would i plug in the value of numbers i got ? sorry im really confused

Answer 5

yep E=6.18E-26J/photon, h=6.626E-34Jsec.

so, \(\nu=\dfrac{6.18E-26J/photon}{6.626E-34Jsec}\)

Answer 6

v=93268940.54...then divide that by 10^6

Answer 7

indeed

Answer 8

how does the photon cancel out when i divde by 10^6 sec-

Answer 9

i'm not sure which constant cancels it out, i've never written it like that, though it's defined as per photon.

Answer 10

thank you... could i ask you another question in a couple of mins?

Answer 11

no problem! sure, post it in a new thread if you don't mind, in case i have to leave.

Answer 12

will do