A local AM radio station broadcasts at a frequency of 698 KHz.

Calculate the energy of the frequency at which it is broadcasting.
Energy = kJ

(1 KHz = 103 sec -1)

Question

A local AM radio station broadcasts at a frequency of 698 KHz.

Calculate the energy of the frequency at which it is broadcasting.
Energy =   kJ

(1 KHz = 103 sec -1)

aaronq · Answer

it's the same concept, now they're giving you other values.

$E=h\nu$

make sure you convert kHz to $sec^{-1}$ first.

anonymous · Answer

i got 4.62e-31

aaronq · Answer

That's like really small. I'm not sure if it's right

anonymous · Answer

this is what i did... convert 698KHz*10^3/1KHz=698000sec- since h=6.626x10^-34j/sec 
then 698000sec-*(6.626x10^-34j/sec)=4.62e-28l
then i converted j to kj by 4.62e-28j*(.001kj/1j)=4.62e-31

aaronq · Answer

then it's right, sorry, i'm just not familiar with the energies of radio wave photons.

anonymous · Answer

its okay thank you!

aaronq · Answer

no problem, good job !

anonymous · Answer

:)