Question

solved

Answer 1

I've tried that and the values for x1 and x2 are wrong. :s

Answer 2

first solve \[z^2-4z+3=0\] then replace \(z\) by \(e^{2x}\)

Answer 3

you can almost do it in your head
you get
\[e^{2x}=1\] or \[e^{2x}=3\]

Answer 4

OHHH I see what I did wrong now.

Answer 5

wait, no I'm still getting answers <0. When I convert it back to e^(4x)-4e^(2x)+3=0

Answer 6

wait I think I have it now, it's 2x = Ln 1 or ln 3

Answer 7

yep that's it.