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Mathematics 8 Online
OpenStudy (anonymous):

Use Bayes' theorem or a tree diagram to calculate the indicated probability. Round your answer to four decimal places. Y1, Y2, Y3 form a partition of S. P(X | Y1) = .1, P(X | Y2) = .8, P(X | Y3) = .1, P(Y1) = .3, P(Y2) = .2. Find P(Y1 | X).

ganeshie8 (ganeshie8):

P(Y1 | X ) = P(Y1 AND X) / P(X)

ganeshie8 (ganeshie8):

find them and plugin

ganeshie8 (ganeshie8):

P(Y1 AND X) = P(Y1) * P(X | Y1) = 0.3 * 0.1

ganeshie8 (ganeshie8):

any idea how to find P(X) ?

OpenStudy (anonymous):

would it be .1?

ganeshie8 (ganeshie8):

P(X) = P(X| Y1) * P(Y1) + P(X | Y2) * P(Y2) + P(X | Y3) * P(Y3)

ganeshie8 (ganeshie8):

P(X) = 0.1 * 0.3 + 0.8 * 0.2 + 0.1 * 0.5

ganeshie8 (ganeshie8):

simplify

OpenStudy (anonymous):

.24?

ganeshie8 (ganeshie8):

yes, thats the probability for P(X) plugit in the formula

ganeshie8 (ganeshie8):

if we had worked this using tree diagams, things wud have been bit clear ...

ganeshie8 (ganeshie8):

finish the problem first, then we can try to visualize it using tree diagram maybe /

OpenStudy (anonymous):

sweet i got it! (.3*.1)/.24 = .125

ganeshie8 (ganeshie8):

thats correct ! lets draw tree diagram now

ganeshie8 (ganeshie8):

Y1, Y2, Y3 form a partition of S

ganeshie8 (ganeshie8):

|dw:1396247032673:dw|

ganeshie8 (ganeshie8):

since the probability must equal 1, P(Y3) must equal 0.5

ganeshie8 (ganeshie8):

|dw:1396247127069:dw|

ganeshie8 (ganeshie8):

^^

ganeshie8 (ganeshie8):

fine, so far ?

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