Use Bayes' theorem or a tree diagram to calculate the indicated probability. Round your answer to four decimal places. Y1, Y2, Y3 form a partition of S. P(X | Y1) = .1, P(X | Y2) = .8, P(X | Y3) = .1, P(Y1) = .3, P(Y2) = .2. Find P(Y1 | X).
P(Y1 | X ) = P(Y1 AND X) / P(X)
find them and plugin
P(Y1 AND X) = P(Y1) * P(X | Y1) = 0.3 * 0.1
any idea how to find P(X) ?
would it be .1?
P(X) = P(X| Y1) * P(Y1) + P(X | Y2) * P(Y2) + P(X | Y3) * P(Y3)
P(X) = 0.1 * 0.3 + 0.8 * 0.2 + 0.1 * 0.5
simplify
.24?
yes, thats the probability for P(X) plugit in the formula
if we had worked this using tree diagams, things wud have been bit clear ...
finish the problem first, then we can try to visualize it using tree diagram maybe /
sweet i got it! (.3*.1)/.24 = .125
thats correct ! lets draw tree diagram now
Y1, Y2, Y3 form a partition of S
|dw:1396247032673:dw|
since the probability must equal 1, P(Y3) must equal 0.5
|dw:1396247127069:dw|
^^
fine, so far ?
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