Question

Solve the separable differential equation.
y' = 3 y^2
Using the initial condition: y(3)= 3, find y(1).

Answer 1

I figured out -1/(3x+c) What next?

Answer 2

lol I already told you

Answer 3

\(y(3)=3\implies 3=\frac{-1}{3*3+c}\implies27+3c=-1\implies3c=-28\)

Answer 4

so now we know what c is

Answer 5

now plug in 1

Answer 6

Ok