Question

Simplify the radical expression.

Answer 1

\[\sqrt{\frac{ 20x^13y^5 }{ 5xy^7}} = \sqrt{\frac{ 4x^{12}}{ y^2}}\]

Answer 2

5 goes in 20, x in x^13, y^7 in y^5

Answer 3

Corrected:\[\sqrt{\frac{ 20x^{13}y^5 }{ 5xy^7}} = \sqrt{\frac{ 4x^{12}}{ y^2}}\]

Answer 4

Thank you c: Can you help with like 3 more?

Answer 5

\[\frac{ \sqrt{4x^{12}} }{ \sqrt{y^2}}\]

Answer 6

Finally\[ \frac{ 2x^6}{ y }\]

Answer 7

Let's see :)

Answer 8

a:\[(3+\sqrt{6})(3-\sqrt{6}) \rightarrow 9 - (\sqrt6)^2 \rightarrow 9-6 =3\]

Answer 9

b:\[5\sqrt7+2\sqrt{175} \rightarrow 5\sqrt7+2\sqrt{7\times25} = 5\sqrt7 + 2*5\sqrt7=15\sqrt7\]

Answer 10

c:
You'll have to square both sides to remove the radicals...
which does leave you with\[5x -1= 4x+9\]collecting like terms:\[x=10\]

Answer 11

I hope you understood the steps.

Answer 12

You're amazing ^.^ Thank you

Answer 13

Ah, you too! Thanks a bunch :)