Mathematics
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OpenStudy (jazzyfa30):
solve each equation. give an exact solution and a four-decimal place approximation.
7. 5^(2x)=12
8, ln(x+3)=2
9. 4^(x-2)=3
10. 2^(x-3=6^(1-2x)
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OpenStudy (jazzyfa30):
@ganeshie8
ganeshie8 (ganeshie8):
if u see exponents in the equation,
and if u dont see logs anywhere, then taking log both sides is a good idea
ganeshie8 (ganeshie8):
\(\large 5^{2x}=12\)
take log both sides
\(\large \log( 5^{2x})= \log (12)\)
ganeshie8 (ganeshie8):
next, u need to knw few log properties :
\(\large \log_a (b)^m = m ~\log_a b\)
ganeshie8 (ganeshie8):
use it
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OpenStudy (jazzyfa30):
how do i break down 12
ganeshie8 (ganeshie8):
\(\large 5^{2x}=12\)
take log both sides
\(\large \log( 5^{2x})= \log (12)\)
\(\large 2x~\log( 5)= \log (12)\)
ganeshie8 (ganeshie8):
divide both sides by \(\log (5)\)
ganeshie8 (ganeshie8):
\(\large 5^{2x}=12\)
take log both sides
\(\large \log( 5^{2x})= \log (12)\)
\(\large 2x~\log( 5)= \log (12)\)
\(\large 2x = \frac{\log (12)}{\log(5)}\)
ganeshie8 (ganeshie8):
use ur calculator and find out both logs on right hand side
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ganeshie8 (ganeshie8):
and divide
OpenStudy (jazzyfa30):
log12 is 1.079181246 and log5 is .6989700043
ganeshie8 (ganeshie8):
yes, divide them
OpenStudy (jazzyfa30):
log 12/log5 is 1.543959311
ganeshie8 (ganeshie8):
yes !
so,
\(\large 5^{2x}=12\)
take log both sides
\(\large \log( 5^{2x})= \log (12)\)
\(\large 2x~\log( 5)= \log (12)\)
\(\large 2x = \frac{\log (12)}{\log(5)}\)
\(\large 2x = 1.543959311\)
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ganeshie8 (ganeshie8):
solve \(x\)
OpenStudy (jazzyfa30):
1.543959311/2 is .7719796555
ganeshie8 (ganeshie8):
correct ! round it as asked...
OpenStudy (jazzyfa30):
1
ganeshie8 (ganeshie8):
whut
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ganeshie8 (ganeshie8):
.7719796555
rounded to four decimal places is
.7720
OpenStudy (jazzyfa30):
ohhh ok i didnt learn that
OpenStudy (jazzyfa30):
its time for lunch when i come back i will let you know so we can finish and thank you so much
ganeshie8 (ganeshie8):
enjoy ur dinner !
ganeshie8 (ganeshie8):
lol here its dinner time in india :)
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OpenStudy (jazzyfa30):
im back
OpenStudy (jazzyfa30):
@ganeshie8
ganeshie8 (ganeshie8):
hey sorry, missed this...
ganeshie8 (ganeshie8):
for next question,
base of ln is always \(e\)
ganeshie8 (ganeshie8):
\(\large \ln(x+3)=2\)
is same as
\(\large \ln_e(x+3)=2\)
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ganeshie8 (ganeshie8):
change it to exponent form...
OpenStudy (jazzyfa30):
e^2=x+3
ganeshie8 (ganeshie8):
yes, solve \(x\)
ganeshie8 (ganeshie8):
and keep in mind, "e" is just a NUMBER, like "pi"
OpenStudy (jazzyfa30):
x=1
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ganeshie8 (ganeshie8):
how ?
ganeshie8 (ganeshie8):
e^2 = x + 3
subtract 3 both sides
e^2 - 3 = x
OpenStudy (jazzyfa30):
5.389
ganeshie8 (ganeshie8):
try again
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ganeshie8 (ganeshie8):
you should get
x = 4.3891
OpenStudy (jazzyfa30):
i see it now