Verify each identity. Show work.

1. (sin(x) - cos(x)/cos(x)) +1 = tan(x)
2. (1/tan(x)) - (sin(x)/cos(x) -1) = -csc(x)
3. (1+tan^2(x)/sin^2(x)+cos^2(x))=sec^(x)
4. (1/tanB)+tanB=secB cscB

Question

Verify each identity. Show work.

1. (sin(x) - cos(x)/cos(x)) +1 = tan(x)
2. (1/tan(x)) - (sin(x)/cos(x) -1) = -csc(x)
3. (1+tan^2(x)/sin^2(x)+cos^2(x))=sec^(x)
4. (1/tanB)+tanB=secB cscB

elisaneedshelp · Answer

I suck at Math Sorry :(

espex · Answer

You are basically just showing that left hand side is equal to the right.
Your first one for example $$\frac{\sin(x) - \cos(x)}{\cos(x)} + 1 = \tan(x)$$ can be rewritten as $$\frac{\sin(x)}{\cos(x)} - \frac{\cos(x)}{\cos(x)} + 1 = \tan(x)$$ where all you are doing is breaking the fraction. Any time you have something over itself, it equals 1 $$\frac{\sin(x)}{\cos(x)} - 1 + 1 = \tan(x)$$ ultimately giving you $$\frac{\sin(x)}{\cos(x)} = \tan(x)$$ Which is true. Just carry on in the same manner with the rest of them.
Good luck.

anonymous · Answer

@Kainui @danisxl21 @agent0smith @ybarrap

kainui · Answer

Just start by turning everything into sine and cosine.

tanx=sinx/cosx
secx=1/cosx
cscx=1/sinx
sin^2x+cos^2x=1

Those are some good trig identities to get you started. Good luck, if you get stuck at a specific spot, show us your work up to where you get stuck and we can help you on that part.