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Mathematics 16 Online
OpenStudy (anonymous):

aetrgadrg

OpenStudy (anonymous):

@phi @surjithayer

OpenStudy (anonymous):

@sourwing

OpenStudy (whpalmer4):

The general form of a circle is \[(x-h)^2 + (y-k)^2=r^2\] We have three points that we know are on the circle. If you plug each point in to the formula as \((x,y)\), you'll get three equations in three unknowns (\(h,k,r)\) and that is sufficient to find the values of those three unknowns.

OpenStudy (anonymous):

ok thanks

OpenStudy (whpalmer4):

You can solve them by taking the first two equations and setting them equal to each other via the common \(r^2\) they share. Do the same with the second two equations. That will give you two equations in only two variables, and I think you won't have any trouble solving them. Use the values you found to find \(r\), then fill in your formula.

OpenStudy (anonymous):

yup i got it. thanks

OpenStudy (whpalmer4):

Oh, you're one of those people who obliterates the question after someone invests the time in helping you. Why do you do that?

OpenStudy (anonymous):

old habits

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