How many grams of lithium chloride must decompose to produce 56.8 milliliters of lithium metal, if the density of lithium is 0.534 g/mL? Show all steps of your calculation as well as the final answer. LiCl → Li + Cl2
Find the mass of the lithium metal.\[m = \rho V\] Next, find the number of moles of lithium metal. (moles = mass / molar mass) Then, find out how many moles of lithium chloride are required. (Use the balanced equation to determine the mole ratio of lithium chloride to lithium metal) Finally, convert the number of moles to lithium chloride to the mass required. (Multiply the number of moles of lithium chloride by the molar mass of lithium chloride)
thanks that helped a lot
2LiCl ---> 2Li + Cl2 mass of Li m= 56.8mL*0.534g/mL = 30.3312 g Li mass of LiCl: 30.3312g Li*1mol Li/6.94g Li*2mol LiCl/2mol Li*42.394gLiCl/1molLiCl = 185.2826g LiCl 185.28 gLiCl Decomposes
is this right
yes.
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