Question

if u burn 59.1 g of hydrogen and produce 528 g of water, how much oxygen reacted

Answer 1

\[2\text{H}_{2(g)} + \text{O}_{2(g)} \longrightarrow 2 \text{H}_2\text{O}_{(g)}\] You don't really "burn" hydrogen gas, as in a combustion reaction. It reacts with oxygen gas in the air to produce water, as above.

Find the number of moles of hydrogen gas in 59.1 g of hydrogen gas.

Hydrogen gas reacts with oxygen gas in 2 : 1 mole ratio. Use this to determine the number of moles of oxygen gas that will react.

Once you have the number of moles of oxygen gas required, convert That number of moles to the mass of oxygen gas, if necessary. You haven't said if the amount of oxygen required has to be expressed in moles or in grams.

Answer 2

in Grams

Answer 3

ok. Find the mass of oxygen in grams once you work out the number of moles of oxygen gas.