Question

What is the standard form of the equation of the conic given by 2x^2 + 2y^2 + 4x - 12y - 22 = 0 ?

Answer 1

2(x^2+2x+1)+2(y^2-6y+3)=30
2(x+1)^2+2(y-sqrt(3))^2=30
(X+1)^2+(y-sqrt(3))^2=15

Answer 2

Then how do I convert it to standard form?

Answer 3

Sorry, I don't really understand what you mean by "standard form"... If you can give me an example, then I might try again :D

Answer 4

like make it equal to 1

Answer 5

That's simple! You just need to divide both sides of the equation by 15!

Answer 6

ok thank you!