Question

lim as x approaches 2 of 1/(x-2)^2

Answer 1

no chance
denominator is 0, numerator is not

Answer 2

It doesn't exist... the limit as x->2, x > 2 = infinity, x->2, x < 2 is -infinity

Answer 3

oh wait it's squared, nvm then it still doesn't exist because it's infinity

Answer 4

1/inf = 0

Answer 5

so the limit does not exist?

Answer 6

Well you could say it's infinity... but technically it doesn't exist

Answer 7

ca you explain to me how please?

Answer 8

Think of what the question is asking. "Find the limit as x approaches 2" is asking "find what value this function approaches as x approaches 2." Since as x approaches 2, the denominator in the function gets smaller and smaller and smaller, then the value of the function gets bigger and bigger and bigger. You can't actually have a value for 1/(2-2)^2 but for 1/(2.00000001-2)^2 you'll have 1/.00000001^2 which, if you put into your calculator, is a very, very big number.

If you have a graphing calculator I'd recommend just typing the function in and looking at it, sometimes the picture can help you organize it in your head.