Question

Solve, using the substitution method.

3x + 2y = 11
x – 2 = – 4y
A.(4,-1/2)


B.(12,-5/2)




C.(0,-2)


D.(0,-1/2)

I got D is that right?

Answer 1

Hi, my name is Stephen. How are you, Ariarose? I see you like cute little girls. I think they're adorable, too (:

3x + 2y = 11
x - 2 = -4y

So, we want to use elimination. What, when multiplied, will cancel out y?

This is a tough one... if we look at substitution, we can add 2 to both sides and isolate x.

3x + 2y = 11
x = -4y + 2

Now, we plug in x...

3(-4y + 2) + 2y = 11

Solve for y. Once you have y, plug it into either equation to solve for x.

Answer 2

add 2 to second equation . it becomes

\[x=2-4y\]

now put it into first equation.

\[3 (2-4y) + 2y = 11\]

\[6-12y + 2y =11 \implies 6-10y=11 \implies y = -\frac{ 1 }{ 2 }\]

now put it into any equation to get \[x = 4\]

so solution is \[ A(4, -\frac{ 1 }{ 2 })\]

Answer 3

Good job, crazysignh. I appreciate your work. (:

Answer 4

ohh ok Thank you both so much! :D I wish we could give 2 medals out i would give both of you one :D

Answer 5

Technically you \(\ could \) use elimination to solve this xD