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Mathematics 8 Online
OpenStudy (anonymous):

determine whether series diverges or converges

OpenStudy (anonymous):

OpenStudy (anonymous):

I believe limit compassion test will do the job

OpenStudy (anonymous):

yes @sourwing but I'm having trouble working it out

OpenStudy (anonymous):

just compare with 1/k. The trick is that, since k is positive, 1/k = 1/sqrt(k^2)

OpenStudy (anonymous):

so you have 1/sqrt(k(k+1)) divides 1/sqrt(k^2). Then take the limit

OpenStudy (anonymous):

I believe the limit is 1, which is finite and positive. And since 1/k is divergent, the original series is also divergent

OpenStudy (anonymous):

wow thank you! let me see if i am able to work it through!

OpenStudy (anonymous):

@sourwing I got it :)

OpenStudy (kainui):

I don't think that will work since 1/k is larger than 1/sqrt(k(k+1))

OpenStudy (anonymous):

the test was "Limit" Comparison test, not Comparison test.

OpenStudy (kainui):

|dw:1396334291859:dw| See if they were the other way around, then you could show that it converges.

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