I need to sum 1/n^2, n=1 to infinity
not to easy
http://math.stackexchange.com/questions/183316/how-to-get-to-the-formula-for-the-sum-of-squares-of-first-n-numbers So if you scroll down a little there's a nice derivation of the formula. Anything that you don't understand I can explain but at the very top there's the formula n(n+1)(2n+1)/6 where n is the highest number.
Of course you need to plug in 1/n for n into the formula to make it work since your problem is only slightly different.
you can find many proofs on the internet, pick one that makes since to you. If you know the expansion of sin(x) I would suggest using that one....
Yeah I'm pretty sure my method isn't going to work out haha.
This may be it, but im still looking
Yes, it's a well known result that it is pi^2/6 and I first saw it with the power series of sinx divided by x equated with another infinite sum. Pretty cool.
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