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Chemistry 7 Online
OpenStudy (anonymous):

Consider an ionic compound, MX, composed of generic metal M and generic, gaseous halogen X.The enthalpy of formation of MX is ΔHf° = –423 kJ/mol. The enthalpy of sublimation of M is ΔHsub = 119 kJ/mol. The ionization energy of M is IE = 469 kJ/mol. The electron affinity of X is ΔHEA = –301 kJ/mol. (Refer to the hint). The bond energy of X2 is BE = 161 kJ/mol. Determine the lattice energy of MX.

OpenStudy (anonymous):

Please somebody help :/ We never covered this topic so I am completely lost!!!

OpenStudy (anonymous):

err I tried it on my own and failed.. I tried googled and failed......... CALL THE TEACHER!!!! Or simple.. Don't do it

OpenStudy (anonymous):

I tried to google it and it brought me to my own question... -_-

OpenStudy (aaronq):

\(E_{Lattice~Energy} =\Delta H^o_f -(\Delta H_{sub}+IP+\dfrac{\Delta H_{BE}}{2})-\Delta H_{EA}\)

OpenStudy (aaronq):

this is in your textbook (or it should be if you're learning it)

OpenStudy (anonymous):

Thank you!

OpenStudy (toxicsugar22):

@damarcusm can you please help me in chem

OpenStudy (anonymous):

I can try

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