Question

HELP PLEASE!!!



Think of an instance in your everyday life where you could use the help of a system of linear equations.

Answer 1

what is question

Answer 2

show me your question

Answer 3

Easy !!

INSTANCE:

I am an owner of a store that sells computers.
there are two factories/companies in town that produce them, sell (to stores) and deliver them in big numbers.

Company 1
charges 2000 dollars for the delivery of all computers together, and for each computer (the cost to buy is) 200 dollars.

Company 2
charges 1000 dollars for the delivery of all computers together, and for each computer (the cost to buy is) 300 dollars.

So I, the owner of a store want to buy a certain number of computers for a store. How would it be cheaper to buy from company 1 or company 2?

SOLUTION:
write linear equation for each company.

Company 1: y=200x+2000
Company 2: y=300x+1000

(where IN BOTH EQUATIONS x is the number of computers, y-intercept is the delivery fee, and y is the total cost.

if you set them equal to each other you will find the number computers (x) that would cost the same in total.
200x+2000=300x+1000 solve for x,

STEP 1:

200x + 2000 = 300x + 1000
-200x -200x

you get 2000=100x+1000



STEP 2:
2000 = 100x + 1000
-1000 -1000

you get 1000=100x


STEP 3: (final step)

1000 = 100x
÷10 ÷10

x=10


SO, when you buy 10 computer you will have to pay the same price in both companies.


From 11 computers and more a cheaper deal (that costs less for the buyer/store-owner ) company 1 is better (better meaning cheaper)
(Prove)
Company 1: y=200x+2000 x=11 , 200(11)+2,000=2,200+2,000=3,800
Company 2: y=300x+1000 x=11 , 300(11)+1,000=3,300+1,000=4,300

From 9 computers and less company 2 is better. (better meaning cheaper)
(Prove)
Company 1: y=200x+2000 x=9 , 200(9)+2000=1800+2000=3800
Company 2: y=300x+1000 x=9 , 300(9)+1000=2700+1000=3700


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