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Mathematics 13 Online
OpenStudy (anonymous):

n a study of 235 adults, the mean heart rate was 82 beats per minute. Assume the population of heart rates is known to be approximately normal with a standard deviation of 5 beats per minute. What is the 98% confidence interval for the mean beats per minute?

ganeshie8 (ganeshie8):

Confidence interval = \(\large \overline{x} \pm Z^* \frac{s}{\sqrt{n}}\)

ganeshie8 (ganeshie8):

you knw : \(\overline{x} = 82\) \(s = \mu = 5\) \(n = 235\)

ganeshie8 (ganeshie8):

find out the \(Z^*\) and plugin above^

OpenStudy (anonymous):

Oh my head hurts already.

ganeshie8 (ganeshie8):

mine too

OpenStudy (anonymous):

Oh good so I'm not alone. I'm so close to just guessing and hoping I'm right.

ganeshie8 (ganeshie8):

my head hurts cuz urs hurts, not becoz problem is scary :/

OpenStudy (anonymous):

My mind was designed for english.

ganeshie8 (ganeshie8):

why u doing math ?

OpenStudy (anonymous):

I believe the answer is 80.9 – 83.3. Because I must, I have a duel enrollment test for college on thuresday.

ganeshie8 (ganeshie8):

doesnt look right

ganeshie8 (ganeshie8):

if u want answer : \((81.24, ~82.76)\)

ganeshie8 (ganeshie8):

it is simple to calculate it on ur own by finding \(Z^*\), but u seem to be either in rush or dont wanto learn

OpenStudy (anonymous):

I do wan't to learn it, I am just not good at square roots and shy away as soon as I see the square root sign. Kinda like a phobia.

ganeshie8 (ganeshie8):

feed it to wolfram friend : http://www.wolframalpha.com/input/?i=82++-+2.33*5%2Fsqrt%28235%29

ganeshie8 (ganeshie8):

you're not supposed to do anything by hand - not efficient

ganeshie8 (ganeshie8):

just figure out the values, and plug them in ur calculator... nobody takes square roots or divisions by hand... I bet you're allowed a scientific calculator to ur stat exam

OpenStudy (anonymous):

Thank you so much. I appreciate your time and I do apoligize if it seemed like all I wan't is a hand out.

ganeshie8 (ganeshie8):

np :)

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