Question

write the trig expression in terms of sine and cosine, then simplify: Sin(x)Sec(x)

Answer 1

\[we~~~know~~~that~~~~~~\sf Sec(x)=\frac{1}{Cos(x)}\]

so your equation turns into
\[\sf Sin(x)\times \frac{1}{Cos(x)}\]
and that's the same as
\[\sf \frac{Sin(x)}{Cos(x)}\]


can you tell me the answer now, or you need more help?
(don't hesitate to reply!)

Answer 2

Tan(x) Thank you, I don't understand these trig functions at all!

Answer 3

What exactly do you not understand about them?

You mean this type of problems that you don't get? or how to find a tan of an angle or what?

Answer 4

These types of problems.

Answer 5

Here are some identities. Knowing these identites and applying them will help you. the more you practice the better you will get. (I also went through that)


\(\LARGE\color{blue}{ \sf Sin(x) }\)\(\Huge\color{blue}{ \sf =\frac{1}{Csc(x)} }\) \(\LARGE\color{blue}{ \sf Csc(x) }\)\(\Huge\color{blue}{ \sf =\frac{1}{Sin(x)} }\)

\(\LARGE\color{blue }{ \sf Cos(x) }\)\(\Huge\color{blue}{ \sf =\frac{1}{Sec(x)} }\) \(\LARGE\color{blue}{ \sf Sec(x) }\)\(\Huge\color{blue}{ \sf =\frac{1}{Cos(x)} }\)

\(\LARGE\color{blue}{ \sf Tan(x) }\)\(\Huge\color{blue}{ \sf =\frac{1}{Cot(x)} }\) \(\LARGE\color{blue}{ \sf Cot(x) }\)\(\Huge\color{blue}{ \sf =\frac{1}{Tan(x)} }\)

also te Pythagorean identities. HERE....

Answer 6

oops, I posted the blue once awkwardly.

Answer 7

Its okay! So how about the problem tan^2(x)-sec^2(x)... I have it to Sin^2(x)/Cos^2(x)-1/cos^2(x)... but I have no clue where to go from there...:(

Answer 8

combine the fractions

Sin^2(x)/Cos^2(x)-1/cos^2(x)

[ Sin^2x-1 ] / Cos^2x

[-Cos^2x / Cos^2x]

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