Ask your own question, for FREE!
Physics 8 Online
OpenStudy (anonymous):

hlp

OpenStudy (johnweldon1993):

Well we know that to calculate the electric field..we use \[\large E = \frac{F}{C}\] if we know E to be .50 N/C and the force experienced to be 2.50 x 10^4 ...we can solve for C \[\large C = FE\] \[\large C = 2.50 \times 10^4 \times .50 = \space ?\]

OpenStudy (johnweldon1993):

You tell me...I was going off what you wrote in the question :)

OpenStudy (johnweldon1993):

Correct....which would be?

OpenStudy (johnweldon1993):

I hate stupid mistakes....looks like I need to go back to algebra xD

OpenStudy (johnweldon1993):

\[\large E = \frac{F}{C}\] \[\large C = \frac{F}{E}\]

OpenStudy (johnweldon1993):

So \[\large C = \frac{2.50 \times 10^{-4}}{.50}\]

OpenStudy (johnweldon1993):

Correct!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!