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Well we know that to calculate the electric field..we use \[\large E = \frac{F}{C}\] if we know E to be .50 N/C and the force experienced to be 2.50 x 10^4 ...we can solve for C \[\large C = FE\] \[\large C = 2.50 \times 10^4 \times .50 = \space ?\]
You tell me...I was going off what you wrote in the question :)
Correct....which would be?
I hate stupid mistakes....looks like I need to go back to algebra xD
\[\large E = \frac{F}{C}\] \[\large C = \frac{F}{E}\]
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So \[\large C = \frac{2.50 \times 10^{-4}}{.50}\]
Correct!
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