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P4Na(s)+5O2(g)--->P4O10(g) if 2.50 grams of phosphorus is ignited in a flask how many grams of P4O10 are formed?
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I guess there is enough Oxygen present. Is reactant P4? Na is not shown in products. Calculate first amount of reactant, n = m/ M Then you see amounts of moles of P4 and P4O10 are equal. Mass of product is m= n*M
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