how do i find the limit as x approaches infinity of ( e^x/5x^2)
you could use l'hopital's rule if it is not obvious
you know what to do for that?
no can you help me?
take the derivative top and bottom separately
don't use the quotient rule you will have to do it twice
oh okay
\[\lim_{x\to \infty}\frac{e^x}{5x^2}=\lim_{x\to \infty}\frac{e^x}{10x}=\lim_{x\to \infty}\frac{e^x}{10}\]
okay I'm with you so far
you are done at that step, since that limit is \(\infty\)
but really it should be pretty clear that \(e^x\) grows way way way faster than \(5x^2\) making the limit infinity for sure pick for example \(x=100\) the denominator is pretty big, at \(50000\) but the numerator is \(e^{100}\) which is probably too large for your calculator
just checked with wolfram, and \(e^{100}\) has 43 zeros!
lol thank you!
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