you are done at that step, since that limit is \(\infty\)
OpenStudy (anonymous):
but really it should be pretty clear that \(e^x\) grows way way way faster than \(5x^2\) making the limit infinity for sure
pick for example \(x=100\)
the denominator is pretty big, at \(50000\) but the numerator is \(e^{100}\) which is probably too large for your calculator
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
just checked with wolfram, and \(e^{100}\) has 43 zeros!