Question

For y= x^2 ln x, find:
a) dy
b) evaluate dy for x=1, dx= 0.01
Calculus problem, please help!

Answer 1

product rule for this one
\[(fg)'=f'g+g'f\] with
\[f(x)=x^2,f'(x)=2x,g(x)=\ln(x),g'(x)=\frac{1}{x}\]

Answer 2

ooh it is \(dy\)
then take that thing and stick a \(dx\) next to it

Answer 3

Thank you for replying! I'm looking this over so give me a minute. :)

Answer 4

ok so for part a dy= 2xlnx + x^2/x dx

Answer 5

and then for part b I just plug in x and dx and that's it?