Question

Help me Solve Definite Integrals of the following detail: int ((3 * x ^ 3-2 * x ^ 2 +4) / ... x = 1 .. 4)?

Answer 1

\[\Large\sf \int\limits \frac{3x^3-2x^2+4}{...x}dx=1..4\quad ?\]What..? What are all the dots supposed to be?

Answer 2

= 39/2 ?

Answer 3

??

Answer 4

The result is = 39/2?

Answer 5

Your question is not clear.
What is the integral you're trying to solve?
Why did you put a bunch of dots everywhere?

Answer 6

Is this the problem?
\[\Large\sf \int\limits_1^4 \frac{3x^3-2x^2+4}{x}dx\]

Answer 7

missed by dividing the x ^ 2

Answer 8

\[\int\limits_{1}^{4}\frac{ 3x^3-2x^2+4 }{ x^2}\]