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Calculus1 14 Online
OpenStudy (adamconner):

need help finding maxima and minima for fx=x3-3x2-1!!!!

OpenStudy (praxer):

Step 1. Find $$\huge f′(x)$$ first . Step 2. Find the points where $$\huge f′(x)$$ is equal to 0. Step 3. Find $$ \huge f′′(x)$$ at those points. Step 4. If the value is negative than it is the maxima and negative than minima.

OpenStudy (adamconner):

ok, so f'x= 3x^2-6x

OpenStudy (adamconner):

the zeros are 0 and 2

OpenStudy (adamconner):

how do I find f''x at those points?

OpenStudy (adamconner):

the second derivative is 6x-6

OpenStudy (adamconner):

do i plug them in there?

OpenStudy (praxer):

differentiate $$\huge f'(x) $$ again. Then u will find f''x

OpenStudy (praxer):

yes, plug the values of the zeroes of the equation in 6x-6

OpenStudy (adamconner):

ok, for 0 its negative and for 2 its positive

OpenStudy (adamconner):

now what?

OpenStudy (praxer):

If the value is negative then it is the maxima and negative than minima.

OpenStudy (praxer):

#if positive than minima.

OpenStudy (adamconner):

ok thanks!

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