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need help finding maxima and minima for fx=x3-3x2-1!!!!
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Step 1. Find $$\huge f′(x)$$ first . Step 2. Find the points where $$\huge f′(x)$$ is equal to 0. Step 3. Find $$ \huge f′′(x)$$ at those points. Step 4. If the value is negative than it is the maxima and negative than minima.
ok, so f'x= 3x^2-6x
the zeros are 0 and 2
how do I find f''x at those points?
the second derivative is 6x-6
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do i plug them in there?
differentiate $$\huge f'(x) $$ again. Then u will find f''x
yes, plug the values of the zeroes of the equation in 6x-6
ok, for 0 its negative and for 2 its positive
now what?
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If the value is negative then it is the maxima and negative than minima.
#if positive than minima.
ok thanks!
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