What is the equation of the following line? Be sure to scroll down first to see all answer options. A. y = 2x B. y = x C. y = 3x D. y = - x E. y = -6x F. y = 6x (help me understand this please)
@Gebooors
can you solve for the slope of the line?
i forgot how to :l @nincompoop
slope is a change in y over change in x does this sound familiar?
I'll help you out step by step
Equation is y = kx + b If k > 0, line is rising, ascending
Like x over y?:o @nincompoop i don't understand how to plug in the numbers with that equation D: @Gebooors
geboors, ascending and descending with respect to what point of reference? |dw:1396414513266:dw|
SLOPE \[slope=m=\frac{ \Delta y }{ \Delta x}=\frac{ y_2-y_1 }{ x_2-x_1 }\]
You have e.g. Y = 3x If x = 1, y = 3* 1 = 3 calculate with few small values of x (0.1.2) You find matching line.
too many hands in the pot... should I stop helping?
Ok, I remembered term ascending wrongly.
Go on, nincompoop, I have other questions here awaiting.
hold on, i'm trying to plug in the numbers to @nincompoop's slope thing :o
okay
Myphuong, you have to concentrate one thing at time. You can continue with nincompoop
\[\frac{ 0 - (-3) }{0 - (-1/2)}\]
i think thats how it is ._. probably wrong @nincompoop got it ;D @Gebooors
first, list the coordinates given in the graph
(0,0) & (-1/2, -3)
label them as (x1, y1) & (x2, y2)
I didn't see your slope solution, yeah you are correct
simplify it
0 = x1 0 = y1 -1/2 = x2 -3 = y2 :o
simplify your slope
\[\frac{ 3 }{ 1/2 }\]
can you simplify it further?
like divide it?
your fraction can also be written this way, yes? \[\frac{ 3 }{ 1 }\div \frac{ 1 }{ 2 }\]
it can? o.o i honestly don't know how you got the 1 though
3 is the same thing as 3/1
I put 1 in the denominator to emphasize it
oh alright so do i cross them? orr is it just 3 over 2?
what is the rule when dividing two fractions?
you take the reciprocal of 1/2 and then you multiply it to the other fraction, correct?
Multiply 3 over 1 by the inverse of 1 over 2? :o which could be 2 over 1?
\[\frac{ 3 }{ 1 } \times \frac{ 2 }{ 1 }\]
6 over 1 o: or just 6
yeah! so now we have our slope = 6 do you know the point-intercept form?
sorry something went wrong with openstudy and it kicked me out -_- ahh! its um y = mx + b, right?
I've never heard of point-intercept form, but slope-intercept form sounds like what you want here. You have the slope, and you have the intercept. \[y = mx+b\]is slope-intercept form, where \(m\) is slope and \(b\) is the y-intercept value.
My approach to this problem: your line goes from (-1/2, -3) through (0,0). That means in a change of 1/2 on the x-axis (from -1/2 to 0), the y value changes by 3 (from -3 to 0). Slope is change in y divided by change in x, so our slope is 3/(1/2) or 6/1 = 6. The line goes through the origin so we don't have to worry about a y-intercept — it's 0.
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