Question

For What Value(s) of x does the expression below equal 0?

(x-2)(x+1)/ x(x+3)

Answer 1

set the numerator equal to zero and solve

Answer 2

How ?

Answer 3

solve \[(x-2)(x+1)=0\]

Answer 4

what about the denominator

Answer 5

if you have \[\frac{f(x)}{g(x)}=0\]

if you multiply by g(x) to both sides you get

\[f(x)=0\]

so the zeros are determined by the numerator (provided that g(x) is not zero at the same time)


also, if you have a product of functions equal to zero set each equal to zero and solve

so \[(x−2)(x+1)=0\Rightarrow (x-2)=0\text{ or }(x+1)=0\]

Answer 6

so thats it or is there more to it?