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2sin^2x-cosx-1=0
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cosx= sqrt ( 1-Sin^2x)
Substitute instead of cos
sin^2 = 1- cos^2 so that your equation is 2-2cos^2 -cos -1 =0 \[cos^2(x)+cos(x)-1 =0 \]let cos(x) = t it turns to t^2 +t-1=0 solve for t then plug back to solve for x
yeah, the other way ( sin = sqrt( 1- cos62x) ) works too
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