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Express the series below in summation notation for the specified number of terms. 7. 4 + 8 + 12 + 16 + 20
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\[\sum_{n=4}^{5}_{?}(n+4)\]
would this be the equation
nope
try again
since u have 5 terms in the series, u need to have the bounds range from 1 to 5, ok ?
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\(\large \sum \limits_{n=1}^5XXX\)
next look at the series : 4 + 8 + 12 + 16 + 20
wat kindof series is it ?
whats the triple x for
arithmetic or geometric ?
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you need to fill in XXX
arithmatic
good, whats the \(n^{th}\) term ?
n1
4 + 8 + 12 + 16 + 20 \(n^{th}\) term = \(4 + (n-1)*4 = 4 + 4n - 4 = 4n\)
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plug that in ur sum notation
so the equation would be \[\sum_{n=1}^{5} 4(n-1)\]
4 + 8 + 12 + 16 + 20 can be represented in sum notation as : \(\large \sum \limits_{n=1}^5 4n\)
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