Question

Express the series below in summation notation for the specified number of terms.
8. 6 + 11 + 16 + 21 + 26 + 31 + 36

Answer 1

start by finding out the \(n^{th}\) term

Answer 2

\[\sum_{n=5}^{7} 6+n\]

Answer 3

nope

Answer 4

why would it be wrong

Answer 5

is the given sequence arithmetic or geometric ?

Answer 6

arithmetic

Answer 7

whats the formula for \(n^{th }\) term ?

Answer 8

6 + 11 + 16 + 21 + 26 + 31 + 36

first term, \(a = 6\)
common difference, \(d = 5\)

so, \(n^{th}\) term = \(a + (n-1)d = ?\)

Answer 9

\[\sum_{n=1}^{7} a+(n-1)d\]

Answer 10

so it would be like this

Answer 11

yes,
plugin \(a\) and \(d\) values

Answer 12

\(\large \sum \limits_{n=1}^7 a+ (n-1)d\)


\(\large \sum \limits_{n=1}^7 6+ (n-1)*5\)

Answer 13

simplify