Mathematics
8 Online
OpenStudy (anonymous):
4. Express the series below in summation notation for the specified number of terms.
a. 2 + 4 + 8 + 16
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OpenStudy (anonymous):
\[\sum_{n=1}^{4} 2(n-1)\]
OpenStudy (anonymous):
@ganeshie8 would this equation be like this
ganeshie8 (ganeshie8):
close, but not right
ganeshie8 (ganeshie8):
plugin n = 1,
do u get first term ?
ganeshie8 (ganeshie8):
2(1-1)
2(0)
0
NOPE
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ganeshie8 (ganeshie8):
check again
OpenStudy (anonymous):
2
OpenStudy (anonymous):
\[\sum_{n=2}^{4} 2(n-1)\]
ganeshie8 (ganeshie8):
not exactly,
n = 2 to 4 is just three terms, but u have four terms in ur given series right ?
ganeshie8 (ganeshie8):
wait a sec,
the given sequence is GEOMETRIC, right ?
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OpenStudy (anonymous):
yes
ganeshie8 (ganeshie8):
find out the \(n^{th}\) term of series first
ganeshie8 (ganeshie8):
2 + 4 + 8 + 16
first term, \(a = 2\)
common ratio, \(r = 2\)
so, the \(n^{th}\) term is ?
OpenStudy (anonymous):
2
ganeshie8 (ganeshie8):
dont remember the \(n^{th}\) term for geometric series ?
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ganeshie8 (ganeshie8):
\(\large a_n = ar^{n-1}\)
ganeshie8 (ganeshie8):
plugin the values
OpenStudy (anonymous):
2(2)^n-1
ganeshie8 (ganeshie8):
yes, so the sum notation can be written as :
\(\large \sum \limits_{n=1}^4 2(2)^{n-1}\)
ganeshie8 (ganeshie8):
simplifying gives u :
\(\large \sum \limits_{n=1}^4 2^{n}\)
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OpenStudy (anonymous):
could we write the equation either way
ganeshie8 (ganeshie8):
either way is fine